InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The position `x` of a particle with respect to time `t` along the x-axis is given by `x=9t^(2)-t^(3)` where `x` is in meter and `t` in second. What will be the position of this particle when it achieves maximum speed along the positive `x` directionA. 32 mB. 54 mC. 81 mD. 24 m |
|
Answer» Correct Answer - B `x=9t^(2)-t^(3)` `v=(dx)/(dt)=18t-3t^(2)` `a=(dv)/(dt)=18-6t` When` v` is maximum, `a=(dv)/(dt)=0` `18-6t=0impliest=3s` At `t=3 s, x=9(3)^(2)-(3)^(3)=54 m` |
|