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The potential difference across the collector of a transistor, used in common emitter mode is 1.5 V, with the collector resistance of `3 kOmega`, the emitter current is [`beta- 50`]A. 0.70mAB. 0.49 mAC. 1.1 mAD. 1.9 mA |
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Answer» Correct Answer - B Here, `V_(CE)`=1.5 V `R_C=3kOmega=3xx10^(3) Omega, beta=50` `therefore I_C=V_(CE)/R_C=1.5/(3xx10^3)=0.5 xx 10^(-3) A` `I_B=I_C/beta=(0.50xx10^(-3))/50=0.01xx10^(-3)A` `I_E=I_C-I_B=(0.50-0.01)xx10^(-3)` `=0.49xx10^(-3) A =0.49 mA` |
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