The present population of a town is 25000. It grows at 4%, 5% and 8% d

1.	The present population of a town is 25000. It grows at 4%, 5% and 8% during first year, second year and third year respectively. Find its population after 3 years.
Answer» Given details are, Present population is = 25000 First year growth R₁ = 4% Second year growth R₂ = 5% Third year growth R₃ = 8% Number of years = 3 By using the formula, A = P (1 + R/100)ⁿ So, population after three years = P (1 + R₁/100) (1 + R₂/100) (1 + R₃/100) = 25000(1 + 4/100) (1 + 5/100) (1 + 8/100) = 25000 (1.04) (1.05) (1.08) = 29484 ∴ Population after 3 years will be 29484.

The present population of a town is 25000. It grows at 4%, 5% and 8% during first year, second year and third year respectively. Find its population after 3 years.

Answer»

Given details are,

Present population is = 25000

First year growth R₁ = 4%

Second year growth R₂ = 5%

Third year growth R₃ = 8%

Number of years = 3

By using the formula,

A = P (1 + R/100)ⁿ

So, population after three years = P (1 + R₁/100) (1 + R₂/100) (1 + R₃/100)

= 25000(1 + 4/100) (1 + 5/100) (1 + 8/100)

= 25000 (1.04) (1.05) (1.08)

= 29484

∴ Population after 3 years will be 29484.