The pressue of a fluid is a linear function of volume (P=a+bV)and the internal energy of the fluide is `U=34+ 3PV`(S.I.units). Find a,b,w, `DeltaE` and q for change is state from `( 100 Pa, 3m^(3))` to `(400 Pa, 6m^(3))`

The pressue of a fluid is a linear function of volume (P=a+bV)and the

1.	The pressue of a fluid is a linear function of volume (P=a+bV)and the internal energy of the fluide is `U=34+ 3PV`(S.I.units). Find a,b,w, `DeltaE` and q for change is state from `( 100 Pa, 3m^(3))` to `(400 Pa, 6m^(3))`
Answer» `W = - underset(V_(1))overset(V_(2))intPdV" "(100 = a + 3b, 400= a +6b, a= - 200 & b = 100)` `W = - underset(V_(1))overset(V_(2))int(a + bV)dV" "- {[aV]+[(bV^(2))/(2)]}_(V_(1))^(V_(2))` ` =- [-600+13.5 xx 100] =- 750` `DeltaU = 6300`

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The pressue of a fluid is a linear function of volume (P=a+bV)and the internal energy of the fluide is `U=34+ 3PV`(S.I.units). Find a,b,w, `DeltaE` and q for change is state from `( 100 Pa, 3m^(3))` to `(400 Pa, 6m^(3))`

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