1.

The pressure of a gas is 100 k Pa. if it is compressed from 1 `m^(3)` to `10 dm^(3)` , find the work done .A. `990 J`B. 9990 JC. 9900 JD. 99000 J

Answer» Correct Answer - D
Given ,
pressure , `p = 100 k Pa = 10^(5)` Pa
Initial volume , `V_(1) = 1m^(3)`
Final volume , `V_(2) = 10 xx 10^(-3) m^(3) = 10^(-2) m^(3)`
W = `p Delta V`
`=10^(5) (1 - 10^(-2)) = 99,000 J`


Discussion

No Comment Found

Related InterviewSolutions