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The pressure of a gas is increased by `50%` at constant temperature. The decrease in volume will be nearest toA. `66%`B. `33%`C. `17%`D. `8%` |
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Answer» Correct Answer - B Let initial pressure, `P_(1)= P, V_(1)=V` Final pressure, `P_(2)=P+50%P` `P=3/2P, V_(2)=?` As temperature is constant `P_(1)V_(1)= P_(2)V_(2)` or `V_(2)= (P_(1)V_(1))/(P_(2))= (PV)/(3P//2)=2/3V` `:.` Decrease in volume `= V-2/3V=V/3` `%` decrease in volume `=(V//3)/Vxx100` `=33.3%~~ 33%` |
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