InterviewSolution
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InterviewSolution
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The pressure `P_(1)and density d_(1)` of a diatomic gas `(gamma=(7)/(5))` change to `P_(2) and d_(2)` during an adiabatic operation .If `(d_(2))/(d_(1))=32, then (P_(2))/(P_(1))`isA. 76B. 128C. 168D. 298 |
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Answer» Correct Answer - B In an adiabatic operation `P_(1)V_(1)^(gamma)=P_(2)V_(2)^(gamma)` `(P_(2))/(P_(1))=(V_(1))/(V_(2))^(gamma)=((m)/(d_(1)))xx(d_(2))/(m)^(gamma)=((d_(2)/(d_(1)))^(gamma)` `P_(2)/(P_(1)=(32)^(7//5)=(2^(5))^(7//5)=26(7)=128` `(P_(2))/(P_(1))=128` |
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