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The pulley arrangements of fig (a) and (b) are identical. The mass of the rope is negligible. In (a) the mass m is lifted up by attaching a mass 2 m to the other end of the rope. In (b) m is lifted up by pulling the other end of the rope with a constant downward force F = 2 mg. Which of the following is correct? |
Answer» In pulling force , ` F = (2mg- T) = 2 mg - mg = mg ` total mass moved , ` = m + 2 m = 3 m ` `:.` Acceleration , ` a = a = ("force")/("mass")= (mg)/(3m )= (g)/(3) ` the pulling force , `F = (2mg-T) = 2 mg - mg = mg ` mass moved = m `:.` Acceleration `a (f)/(m) = (mg)/(m) = g ` , |
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