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The r.m.s. value of the base current ofa transistor is `10mu`A. What is the current gain (`beta`) if the peak value of the a.c. collector current is 1.414 mA ?A. 50B. 75C. 100D. 125

Answer» Correct Answer - C
Peak value of `I_C` = 1.414 mA
`therefore` r.m.s. value of `I_C=1.414/sqrt2`= 1 mA
`therefore beta=I_C/I_B=10^(-3)/(10xx10^(-6)) ` =100


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