InterviewSolution
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InterviewSolution
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The radioactive elements `A` and `B` have half-lives of `15` and 5 minute respectively. Thew experiment begins with 4 times the number the number of `B` atoms as `A` atoms. At which of the followig times does the number fo `A` atoms left equals the number of `B` atoms left:A. `30 "minute"`B. `15 "minute"`C. `10 "minute"`D. `5 "minute"` |
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Answer» Correct Answer - `(b)` For `A: t = (2.303xx15)/(0.693) log ((a)/(x))` For `B: t = (2.303xx5)/(0.693) log ((4a)/(9x))` `= (2.303xx5)/(0.693) [log 4 + log (a)/(x)]` `:. t = 15` minute |
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