The radioactive of a sample is `R_(1)` at a time `T_(1)` and `R_(2)` at a time `T_(2)`. If the half-life of the specimen is `T`, the number of atoms that have disintegrated in the time `(T_(2)-T_(1))` is equal to`(n(R_(1)-R_(2))T)/(ln4) `. Here n is some integral number. What is the value of n?

The radioactive of a sample is `R_(1)` at a time `T_(1)` and `R_(2)` a

1.	The radioactive of a sample is `R_(1)` at a time `T_(1)` and `R_(2)` at a time `T_(2)`. If the half-life of the specimen is `T`, the number of atoms that have disintegrated in the time `(T_(2)-T_(1))` is equal to`(n(R_(1)-R_(2))T)/(ln4) `. Here n is some integral number. What is the value of n?
Answer» Correct Answer - B `R_(1)=lambdaN_(1) , R_(2)=lambda N_(2)` No. of atoms decayed in `T_(1)-T_(2)=N_(1)-N_(2)=(R_(1)-R_(2))/(lambda)` `=((R_(1)-R_(2)))/(log 2)=(2(R_(1)-T_(2)))/(log 4)rArr n=2`

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The radioactive of a sample is `R_(1)` at a time `T_(1)` and `R_(2)` at a time `T_(2)`. If the half-life of the specimen is `T`, the number of atoms that have disintegrated in the time `(T_(2)-T_(1))` is equal to`(n(R_(1)-R_(2))T)/(ln4) `. Here n is some integral number. What is the value of n?

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