InterviewSolution
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InterviewSolution
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The radioactivity of a sample is `R_(1)` at a time `T_(1)` and `R_(2)` at a time, `T_(2)` If the half-line of the secimen is `T`, the number of atoms that have disintergrated in the time `(T_(2) - T_(1))` is proportional to:A. `(R_(1) T_(1) - R_(2)T_(2))`B. `(R_(2) - R_(1))`C. `(R_(2) - R_(1))//T`D. `(R_(2) - R_(1))T//0.693` |
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Answer» Correct Answer - `(d)` `R_(1) = lambda N_(1)`, `R_() = lambda N_(2)`. No, of atoms decayed in time `(T_(2) - T_(1)) = N_(1) - N_(2)` `= (R_(1) - R_(2))/(lambda) = (R_(1) - R_(2))/(0.693) T.` |
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