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The radius of a circle, having minimum area, whichtouches the curve `y=4-x^2`and the lines `y=|x|`is :`4(sqrt(2)-1)`(2) `4(sqrt(2)+1)`(3) `2(sqrt(2)+1)`(4) `2(sqrt(2)-1)` |
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Answer» C(0,4-r) y-x=0 `|(4-r-0)/sqrt2|=r` `4-r=pmsqrt2r` `4=(sqrt2+1)r` `r=4/(sqrt2+1)*(sqrt2-1)/(sqrt2-1)` `=(4(sqrt2-1))/(2-1)` Option 1 is correct. |
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