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The radius of a sphere shrinks from 10 to 9.8 cm. Find approximatelythe decrease in its volume. |
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Answer» Volume of a sphere, `V = 4/3pir^3` `:. (dV)/(dr) = 4/3pi(3r^2)` `=> (dV)/(dr) = 4pir^2` Here, `r = 10cm, dr = 9.8-10 = -0.2cm` `:. (dV)/(-0.2) = 4pi(10)^2` `=>dV = 400pi**(-0.2) = -80pi`. So, decrease in volume of the sphere is `80pi cm^3`. |
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