1.

The radius of a sphere shrinks from 10 to 9.8 cm. Find approximatelythe decrease in its volume.

Answer» Volume of a sphere, `V = 4/3pir^3`
`:. (dV)/(dr) = 4/3pi(3r^2)`
`=> (dV)/(dr) = 4pir^2`
Here, `r = 10cm, dr = 9.8-10 = -0.2cm`
`:. (dV)/(-0.2) = 4pi(10)^2`
`=>dV = 400pi**(-0.2) = -80pi`.
So, decrease in volume of the sphere is `80pi cm^3`.


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