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The radius of first Bohr orbit is x, then de-Broglie wavelength of electron in 3rd orbit is nearlyA. `2px`B. `6px`C. `9x`D. `x//3` |
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Answer» Correct Answer - B `r_(n) = n^(2)r_(1), mv_(n)r_(n) = (nh)/(2pi), lambda = (h)/(mv_(n))` |
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