1.

The radius of orbit of a geostationary satellite is given by _____ (M = Mass of the earth; R = Radius of the earth; T = Time period of the satellite)(a) [(T^2*G*M)/(4*pi^2)]^3/2(b) [(T^2*G*M)/(4*pi^2)]^2/3 – R(c) [(T^2*G*M)/(4*pi^2)]^1/3 – R(d) [(T^2*G*M)/(4*pi^2)]^1/3This question was addressed to me in my homework.My query is from Gravitation in portion Gravitation of Physics – Class 11

Answer»

The correct OPTION is (d) [(T^2*G*M)/(4*pi^2)]^1/3

To explain I would say: The time period of a satellite is given by;

T = 2 X pi x (R+h) ^3/2/ (G x M)^1/2

Solving for ORBITAL radius “(R+h)”, we get;

(R+h) = [(T^2 x G x M)/(4 x pi^2)]^1/3.



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