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The rate constant for a first order reaction at `300^(@)C` for which `E_(a)` is 35 kcal `mol^(-1)` and frequency constant is `1.45 xx 10^(11) s^(-1)` isA. `10 xx 10^(2) s^(-1)`B. `5.37 xx 10^(10) s^(-1)`C. `5 xx 10^(-4) s^(-1)`D. `7.94 xx 10^(-3) s^(-1)` |
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Answer» Correct Answer - D log `k = log A - (E_(a))/(2.303RT)` log k = log `(1.45 xx 10^(11)) - (35 xx 10^(3))/(2.303 xx 2 573)` log k = 11.16 - 13.26 = - 2.1 Taking antilog, `k = 7.94 xx 10^(-3) s^(-1)` |
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