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The rate constant for an isomerisation reaction `Ato B` is `4.5 xx 10^(-3)min^(-1)`. If the initial concentration of A is 1M, Calculate the rate of the reaction after 1 hour. |
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Answer» Step I. Calculating of concentration after 1 h (60 min). `k=2.303/t log ([A])_(0)/([A])_(t)` `(log)[A]_(0)/[A]_(t)=(kt)/(2.303) = ((4.5 xx 10^(-3) min^(-1))xx (60 min))/2.303 = 0.11729` `(log)[A]_(0)/[A]_(t)= Antilog0.1172//9 = 1.310, [A]_(t) = [A]_(0)/1.310 = 0.763M` Step II. Calculation of rate after 1 h(60 min). Rate after 60 min= `k[A]_(t)= 4.5 xx 10^(-3) min^(-1) xx 0.763 M= 3.4354 xx 10^(-3) M min^(-1)` |
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