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The rate constant for an isomerization reaction, `A rarr B` is `4.5 xx 10^(-3) min^(-1)`. If the initial concentration of `A` is `1 M`, calculate the rate of the reaction after `1 h`.A. `0.763 M`B. `1.763 M`C. `2.763M`D. `0.076M` |
Answer» Correct Answer - 1 From the unit of rate constant, it follows that the given isomerization reaction is a first order reaction. The concentration of A after `1h` as determined from the expression. `log.([A])/([A]_(0))=-(k)/(2.303)t` `log.([A])/([A]_(0))=-(4.5xx10^(-3)mi n^(-1))/(2.303)(60 mi n)=-0.1172 mol L^(-1)" "[ As[A_(0)]=1M]` `:. " "[A]=0.7634M` |
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