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The rate constant for the first order reaction is `60 s^(-1)`. How much time will it take to reduce the concentration of the reactant to `1//16th` value ?A. `4.6 xx 10^(4) s`B. `4.6 xx 10^(-4) s`C. `4.6 xx 10^(-2) s`D. `4.6 xx 10^(2) s` |
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Answer» Correct Answer - C For the first order reaction, `k=(2.303)/(t)log.([A_(0)])/([A])` Then, `k=(2.303)/(t)log. ((a)/(a//16))=0.0462=4.62xx10^(-2)s` |
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