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The rate constant for the reaction, `2N_(2)O_(5) rarr 4NO_(2) + O_(2)` is `3.0 xx 10^(-5) s^(-1)`. If the rate is `2.40 xx 10^(-5) mol L^(-1) s^(-1)`, then the initial concentration of `N_(2)O_(5)` (in `mol L^(-1)`) isA. `1.4 (M)`B. `1.2 (M)`C. `0.04 (M)`D. `0.8 (M)` |
Answer» Correct Answer - D Order of rection is 1st `:. [N_(2)O_(5)] = ("rate")/("rate constant") = (2.4 xx 10^(-5))/(3 xx 10^(-5))` `= 0.8 (M)` |
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