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The rate constant for the reaction `2N_(2)O_(5)to4NO_(2)+O_(2), "is"" " 3.0xx10^(-5)S^(-1)`. If the rate is `2.40xx10^(-5)"mol"L^(-1)s^(-1)` then the concentration of `N_(2)O_(5)("in mol" L^(-1))` isA. 1.4B. 1.2C. 0.04D. 0.8 |
Answer» Correct Answer - D For a first order reaction `Rate =k[N_(2)O_(5)]` `2.4xx10^(-5)=3.0xx10^(-5)[N_(2)O_(5)]` `[N_(2)O_(5)]=(2.4xx10^(-5))/(3.0xx10^(-5))=0.8 "mol" L^(-1)` |
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