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The rate constant fro a second order reaction is `8 xx 10^(-5) M^(-1) "min"^(-1)`. How long will in take a `1 M` solution to be reduced to `0.5 M`A. `8 xx 10^(-5)` minB. `8.665 xx 10^(3)` minC. `4 xx 10^(-5)` minD. `1.25 xx 10^(4)`min |
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Answer» Correct Answer - d `8 xx 10^(-5) = (1)/(t) [(1)/(0.5) - (1)/(1)] , 8 xx 10^(-5) = (1)/(t)[2-1]` `t = (1)/(8 xx 10^(-5)) = 0.125 xx 10^(5) = 1.25 xx 10^(4)` min. |
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