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The rate constant `K_(1)` of a reaction is found to be double that of rate constant `K_(2)` of another reaction. The relationship between corresponding activation energies of the two reaction at same temperature `(E_(1) "and" E_(2))` can be represented as:A. `E_(1) gt E_(2)`B. `E_(1) lt E_(2)`C. `E_(1)=E_(2)`D. None of these |
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Answer» Correct Answer - d `K_(1)=A_(1)e^(-E_(1)//RT)` and `K_(2)=A_(2)e^(-E_(2)//RT)` `K_(1)/K_(2)=A_(1)/A_(2)xxe^((E_(2)-E_(1))RT), A_(1)` and `A_(2)` are not given. |
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