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The rate constant of a first order reaction is `2.0 xx 10^(-5)s^(-1)` and the initial concentration is 0.10 mol `L^(-1)`. The initial rate isA. `2.0 xx 10^(-6)"mol " L^(-1)s^(-1)`B. `1.0 xx 10^(-6)"mol " L^(-1)s^(-1)`C. `1.5 xx 10^(-6)"mol " L^(-1)s^(-1)`D. `0.5 xx 10^(-6)"mol " L^(-1)s^(-1)` |
Answer» Correct Answer - A Rate `((dx)/(dt))` = Rate constant (k) `xx` Concentration `=2.0xx10^(-5)s^(-1)xx0.10" mol "L^(-1)` `=2.0 xx 10^(-6)" mol "L^(-1)s^(-1)` |
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