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The rate constant of a reaction increases by 5% when its temperature is raised from `27^@c` to `28^@c.` The activation energy of the reaction isA. `36.6kJ//mol`B. `16.6kJ//mol`C. `46.6kJ//mol`D. `26.6kJ//mol` |
Answer» Correct Answer - A `"log"(k_(2))/k_(1)=E_(a)/(2.303R)xx(T_(2)-T_(1))/(T_(1).T_(2))` log`(105)/(100)=E_(a)/(2.303xx8.314)xx(1)/(300xx301)` `E_(a)=36.65kJ" mol"` |
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