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The rate constant of a second order reaction is `10^(-2) "mol"^(-1) litre sec^(-1)`. The rate constant when expressed in `cm^(3) "molecule"^(-1) min^(-1)` is:A. `9.96xx10^(-22)`B. `9.96xx10^(-23)`C. `9.96xx10^(21)`D. `1.004xx10^(-24)` |
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Answer» Correct Answer - a `K=10^(-2) mol^(-1) litre sec^(-1)` `=(10^(-2)xx1000xx60)/(6.02xx10^(23)) c c "molecule"^(-1) min^(-1)` `=9.9618xx10^(-22) c c "molecule"^(-1) min^(-1)` |
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