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The rate constant of a zero order reaction is` 0.2 mol L^(-3) h^(-1)`. If the concentration of the reactant after 30 min is 0.05 mol ` dm^(-3)`, then its initial concentration would beA. `0.01 "mol dm"^(-3)`B. `0.15 "mol dm"^(-3)`C. `0.25 "mol dm"^(-3)`D. `4.00 "mol dm"^(-3)` |
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Answer» Correct Answer - B For zero order reaction, `x=kt-0.2"mol dm"^(-3)h^(-1)xx(30)/(60)h=0.1"mol dm"^(-3)` Now, concentration `=0.05"mol dm"^(-3)` Hence initial concentration`=0.1+0.05=0.15"mol dm"^(-3)` |
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