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The rate constant of forward and backward reactions for certain hypothetical reaction are `1.1 xx 10^(-2)` and `1.5 xx 10^(-3)`, respectively. The equilibrium constant of the reaction isA. `7.33`B. `0.733`C. `73.3`D. `733` |
Answer» Correct Answer - A `k_(eq) = (1.1 xx 10^(-2))/(1.5 xx 10^(-3)) = 7.33`Correct Answer - A `k_(eq) = (1.1 xx 10^(-2))/(1.5 xx 10^(-3)) = 7.33` |
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