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The rate constant, the activation energy and the Arrhenius parameter of a chemical reaction at `25^(@)C` are `3.0 xx 10^(-4) s^(-1), 104 "kJ mol"^(-1)` and `6.0 xx 10^(14)s^(-1)` respectively. The value of the rate constant as `T rarr oo` isA. `2.0 xx 10^(18)s^(-1)`B. `6.0 xx 10^(14) s^(-1)`C. InfinityD. `3.6 xx 10^(30)s^(-1)` |
Answer» Correct Answer - B The Arrhenius equation is `K = Ae^(-E_(a)//RT)` As `T rarr oo` the value `(Ea)/(RT) rarr 0` & `e^(-E_(a)//RT) rarr e^(-0) rArr 1` Hence `k rarr A` Hence `k = 6.0 xx 10^(14)s^(-1)` |
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