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The rate constants `k_(1)` and `k_(2)` of two reactions are in the ratio `2:1`. The corresponding energies of acativation of the two reaction will be related byA. `E_(1) gt E_(2)`B. `E_(1) gt E_(2)`C. `E_(1)=E_(2)`D. `E_(1)=2E_(2)` |
Answer» Correct Answer - B `k_(1)//k_(2)= 2:1 or k_(1)=2k_(1), i.e., k_(1) gt k_(2)`. Uisng Arrhenius eqaution, `k=Ae^(-E_(a)//RT)` Therefore, if `k` is high `E_(a)` is low. Hence, `E_(2) gt E_(1)` |
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