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The rate of a certain reaction increases by `2.3` times when the temperature is raised form `300K` to `310 K`. If `k` is the rate constant at `300K,` then the rate constant at `310 K` will be equal toA. `2k`B. `k`C. `2.3 k`D. `3 k^(2)` |
Answer» Correct Answer - C Since `k prop T`. Hence, `k_(310K)=2.3k_(300 K)`Correct Answer - C Since `k prop T`. Hence, `k_(310K)=2.3k_(300 K)` |
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