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The rate of a first order reaction is `1.5 xx 10^(-2) mol L^(-1) "min"^(-1)` at 0.5 M concentration of the reactant . The half life of the reaction isA. 8.73 minB. 7.53 minC. 0.383 minD. 23.1 min |
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Answer» Correct Answer - d Rate `((dx)/(dt))` = k.c, `1.5 xx 10^(-2) = k xx 0.5` For first order k = `(1.5 xx 10^(-2))/(0.5) = 3 xx 10^(-2) "minute"^(-1)` `t_(1//2) = (.693)/(k) = (.693)/(3 xx 10^(-2)) = 23.1` minute. |
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