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The rate of a first order reaction is `1.8 xx10 ^(-3 ) "Mol "L^(-1) "Min"^(-1)` . When the initial concentration is `0.3 "Mol "L^(-1) `. The rate constant in the units of second isA. `1xx10^(-2) S^(-1)`B. `1xx10^(-4)S^(-1)`C. `6xx10^(-2)S^(-1)`D. `6xx10^(-4)S^(-1)` |
Answer» Correct Answer - B Rate =k [concentration ]` therefore k=("Rate ")/("[concentration ]")` `=(1.8xx10^(-3))/(0.3)=6xx10^(-3)xx(1)/(60)=10^(-4)` |
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