1.

The rate of a gaseous reaction is given by the expresison `k[A]^(2)[B]^(3)`. The volume of the reaction vessel is suddenly reduced to one-half of the initial volume. The reaction rate relative to the original rate will beA. `1//24`B. `1//32`C. 32D. 24

Answer» Rate `=K[A]^(2)[B]^(3)`
When volume is halved, the concentration will become double.
`:. "Rate"=K[2A]^(2)[2B]^(3)`
`=32 k=K[A]^(2)[B]^(3)=32xx` Original rate from (i)


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