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The rate of a gaseous reaction is given by the expresison `k[A]^(2)[B]^(3)`. The volume of the reaction vessel is suddenly reduced to one-half of the initial volume. The reaction rate relative to the original rate will beA. (a) `1//24`B. (b) `1//32`C. ( c) `32`D. (d) `24` |
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Answer» Correct Answer - C (c ) Rate `= k[A]^(2)[B]^(3)` When the volume is halved, the concentration will become double. `:.` Rate `= k[2A]^(2)[2B]^(3)` `= 32k[A]^(2)[B]^(3)` `= 32 xx` Original rate form Eq. (i). |
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