1.

The rate of a gaseous reaction is given by the expresison `k[A]^(2)[B]^(3)`. The volume of the reaction vessel is suddenly reduced to one-half of the initial volume. The reaction rate relative to the original rate will beA. (a) `1//24`B. (b) `1//32`C. ( c) `32`D. (d) `24`

Answer» Correct Answer - C
(c ) Rate `= k[A]^(2)[B]^(3)`
When the volume is halved, the concentration will become double.
`:.` Rate `= k[2A]^(2)[2B]^(3)`
`= 32k[A]^(2)[B]^(3)`
`= 32 xx` Original rate form Eq. (i).


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