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The rate of a reaction becomes 4 times when temperature is raised from 293 K to 313 K. The activation energy for such reaction would beA. 50.855 kJ `" mol"^(-1)`B. 52.849 kJ `" mol"^(-1)`C. 54.855 kJ `" mol"^(-1)`D. 56.855 kJ `" mol"^(-1)` |
Answer» Correct Answer - B From the Arrhenius equation, `log.(k_(2))/(k_(1))=(E_(a))/(2.303R)[(T_(2)-T_(1)]/(T_(1).T_(2))]` Hence, `log4=(E_(a))/(2.303xx8.314)[(313-293)/(293xx313)]` `E_(a)=(11.521)/(0.000218)=52.849kJ" mol"^(-1)` |
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