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The rate of a reaction doubles when its temperature changes form `300 K` to `310 K`. Activation energy of such a reaction will be: `(R = 8.314 JK^(-1) mol^(-1) and log 2 = 0.301)`A. `53.6 kJ mol ^(-1)`B. `48.6 kJ mol ^(-1)`C. `58.5kJ mol ^(-1)`D. `60.5 kJ mol ^(-1)` |
Answer» Correct Answer - a |
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