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The rate of a reaction quadruples when the temperature changes from `293K` to `313K`. Calculate the energy of activation of the reaction assuming that it does not change with temperature.A. `48.625kJ" mol"^(-1)`B. `654.35kJ" mol"^(-1)`C. `354.20kJ" mol"^(-1)`D. `52.854kJ" mol"^(-1)` |
Answer» Correct Answer - D According to Arrhenius equation, `"log"k_(2)/(k_(1))=E_(a)/(2.303R)[(1)/(T_(1))-(1)/(T_(2))]` `"log"(4)/(1)=E_(a)/(2.303xx(8.314Jmol^(-1)k^(-1)))xx(20)/(293xx313)` `E_(a)=52.854kJmol` |
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