1.

The rate of climb is given by _____________(a) [ηP+DV]\(\frac{1}{W}\)=\(\frac{dH}{dt}\)(b) [ηP-DV]\(\frac{1}{W}\)=\(\frac{dH}{dt}\)(c) [ηP+DV]W=\(\frac{dH}{dt}\)(d) [ηP-DV]W=\(\frac{dH}{dt}\)The question was posed to me during an online interview.My question is taken from Climb and Descent Performance with Power-Producing Engines topic in chapter Climb and Descent Performance of Aircraft Performance

Answer»

The correct answer is (b) [ηP-DV]\(\frac{1}{W}\)=\(\frac{dH}{dt}\)

The best I can explain: The RATE of CLIMB is given by [ηP-DV]\(\frac{1}{W}\)=\(\frac{dH}{dt}\) where η is propeller EFFICIENCY, P is power, V is velocity, D is drag and W is WEIGHT and dH/dt is vertical velocity. The rate of climb is maximum when power speed is minimum.



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