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The rate of first-order reaction is `1.5 xx 10^(-2) M "min"^(-1)` at `0.5 M` concentration of reactant. The half-life of reaction isA. 0.383 minB. 23.1 minC. 8.73 minD. 7.53 min |
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Answer» Correct Answer - B For the first order reaction, Rate =K[A] Given that, `(dx)/(dt)=1..5xx10^(-2)"mol L^(-1)min"^(-1)` `K=? and [A]=0.5 M` `therefore " "1.5xx10^(-2)=Kxx0.5` `therefore" "K=(1.5xx10^(-2))/(0.5)=3xx10^(-2) "min"^(-1)` "For first order reaction" Half-life,period `t_(t//2)=(0.693)/(K)=(0.693)/(3xx10^(-2))=23.1"min` |
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