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The rate of first-order reaction is `1.5 xx 10^(-2) M "min"^(-1)` at `0.5 M` concentration of reactant. The half-life of reaction isA. `0.383min`B. `23.1min`C. `8.73 min`D. `7.53 min` |
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Answer» Correct Answer - B for the first order reaction, `rate((dx)/(dt))=K[A]` [A] = concentration of reactant k= rate constant given that , `(dx)/(dt)=1.5xx10^(-2)molL^(-1)min""^(-1)` `k=?and [A]=0.5M` `therefore 1.5xx10^(-2)=kxx0.5` `therefore k=(1.5xx10^(-2))/(0.5)` `=3xx10^(-2) min^(-1)` for first order reaction , Half -life period `t_(1//2)=(0.693)/(k)=(0.693)/(3xx10^(-2))` `=23.1 min` |
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