InterviewSolution
Saved Bookmarks
| 1. |
The rate of first-order reaction is `1.5 xx 10^(-2) M "min"^(-1)` at `0.5 M` concentration of reactant. The half-life of reaction isA. `0.383 min`B. `23.1 min`C. `8.73 min`D. `7.53 min` |
|
Answer» Correct Answer - B Differential rate law for a first order reaction is Rate `=k[A]` Thus, `k=(Rate)/([A])` `=(1.5xx10^(-2)molL^(-1)min^(-1))/(0.5M)` `=3xx10^(-2)min^(-1)` For a first order reaction `t_(1//2)=(0/693)/(k)=(0.693)/(3xx10^(-2)min^(-1))` `=23.1min` |
|