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The rate of formation of `SO_(3)` in the following reaction is `100 g " min"^(-1).2SO_(2)+O_(2)rarr2SO_(3)` The rate of disappearance of `O_(2)` isA. 29 g `"min"^(-1)`B. 20 g `"min"^(-1)`C. 200 g `"min"^(-1)`D. 50 g `"min"^(-1)` |
Answer» Correct Answer - B `2SO_(2)+O_(2)rarr2SO_(3)` `Rate=-(d[O_(2)])/(dt)=(1)/(2)(d[SO_(3)])/(dt)` The rate of formation of S)_(3) is `(d[SO_(3)])/(dt)=100g min^(-1)=(100)/(80) mol min^(-1)` `[because "molar mass" of SO_(3)=80 g " mol"^(-1)]` `(d[O_(2)])/(dt)=(1)/(2)((100)/(80))mol min^(-1)` `(d[O_(2)])/(dt)=(1)/(2)((100)/(80))xx32gmin^(-1)` `[because "molar mass of "O_(2)=32g" mol"^(-1)]` `=20g" min"^(-1)` |
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