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The rate of reaction `2NO + Cl_(2) to 2NOCl` is doubled when the concentration of `Cl_(2)` is doubled and becomes eight times when the concentration of both NO and `Cl_(2)` are doubled. Predict the order of reaction. |
Answer» Rate ( r) = `k[NO]^(x)[Cl_(2)]^(y)`…………..(i) Rate (2r)`= k[NO]^(x)[2Cl_(2)]^(y)`………..(ii) Rate (8r) = `k[2NO]^(x)[2Cl_(2)]^(y)`…………(iii) `(8r)/(2r) = (k[2NO]^(x)[2Cl_(2)]^(y))/(k[NO]^(x)[2Cl_(2)]^(y))` `4= [2]^(x) or x=2` `(2r)/(r)=(k[NO]^(x)[2Cl_(2)]^(y))/(k[NO]^(x)[Cl_(2)]^(y))` `2= [2]^(y)` or y=1 Order of reaction= 2+1=3. |
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