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The rate of reaction between A and B increases by a factor of 100 , when the concentration of A is increased 10 folds . The order of reaction with respect to A isA. 10B. 1C. 4D. 2 |
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Answer» Correct Answer - d `r = k[A]^(n) , 100 r = k [10A]^(n)` Thus `(1)/(100) = ((1)/(10))^(n) ` or n = 2. |
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