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The rate of reaction between `A` and `B` increases by a factor of `100`, when the concentration with respect to `A` is increased `10` folds, the order of reaction w.r.t. `A` isA. `10`B. `1`C. `4`D. `2` |
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Answer» Correct Answer - D `r = K[A]^(n), 100r = K[10 A]^(n)` Thus `(1)/(100) = ((1)/(10))^(n)` or `n = 2` |
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