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The rate of reaction between two `A` and `B` decreases by factor `4` if the concentration of reactant `B` is doubled. The order of this reaction with respect to `B` isA. `-1`B. `-2`C. 1D. 2 |
Answer» Correct Answer - B `A + B to "product"` ` Rate Iprop [A]^(x)[B]^(y)` the rate decreases by a factor 4 if the concentration of reaction B is doubled `(I)/(4)prop[A]^(x)[2B]^(y)` from Eqs(i) and (ii) `4=((1)/(2))^(y)` `y=-2` hence order of reaction with respect to B is -2. |
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