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The rate of the first-order reaction `X rarr` products is `7.5 xx 10^(-4) mol L^(-1) "min"^(-1)`. What will be value of rate constant when the concentration of `X` is `0.5 mol L^(-1)` ?A. `3.75 xx 10^(-4)s^(-1)`B. `2.5 xx 10^(-5) s^(-1)`C. `1.5 xx 10^(-3) s^(-1)`D. `8.0 xx 10^(-4) s^(-1)` |
Answer» Correct Answer - B Rate of reaction `= 7.5 xx 10^(-4) "mol L"^(-1) "min"^(-1)` `= (7.5 xx 10^(-4))/(60) "mol L"^(-1) s^(-1)` `= 1.25 xx 10^(-5) "mol L"^(-1) sec^(-1)` Rate of reaction `= k["concentration of react ant X"]` Or `k = (1.25 xx 10^(-5))/(0.5) = 2.5 xx 10^(-5) s^(-1)` |
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