The ratio of atomic number of two elements A and B is 1:2 The numebr of electrons present in the valence sheel (3^rd) of A is equal to the difference in the number of electrons present in the other two shells. Steps involved for the calculation of ratio of number of electrons present in a penultimate sheel to anti-penultimate sheel of B are given below : Arrange them in the correct sequence : (1) calculation of atomic number of B (2) calcualtion of valence electrons present in A. (3) calacualtion of atomic number of A. (4)calacualtion of number of electrons present in the penultimate and anti-penultimate shells of B. (5) writing electronic configuration of B.

The ratio of atomic number of two elements A and B is 1:2 The numebr o

1.	The ratio of atomic number of two elements A and B is 1:2 The numebr of electrons present in the valence sheel (3^rd) of A is equal to the difference in the number of electrons present in the other two shells. Steps involved for the calculation of ratio of number of electrons present in a penultimate sheel to anti-penultimate sheel of B are given below : Arrange them in the correct sequence : (1) calculation of atomic number of B (2) calcualtion of valence electrons present in A. (3) calacualtion of atomic number of A. (4)calacualtion of number of electrons present in the penultimate and anti-penultimate shells of B. (5) writing electronic configuration of B.
Answer» 23415 23154 45231 42135 Solution :(i) CALCULATION of valence ELECTORNS present in A (ii) calculation of atomic number of A (III) calcualtion of atomic number of B (IV) writing electronic configuration of B (v) calcualtion of number of electrons present in the penultimate and anti-penultimate shells of B.